public class Solution {
//f[i][j] = min path sum from (0,0) to (i,j)
//f[i][j] = grid[i][j] + min(f[i - 1][j], f[i][j - 1])
public int minPathSum(int[][] grid) {
if (grid == null || grid.length == 0 || grid[0].length == 0) {
return 0;
}
int m = grid.length;
int n = grid[0].length;
int[][] f = new int[m][n];
f[0][0] = grid[0][0];
for (int i = 1; i < m; i++) {
f[i][0] = f[i - 1][0] + grid[i][0];
}
for (int i = 1; i < n; i++) {
f[0][i] = f[0][i - 1] + grid[0][i];
}
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
f[i][j] = Math.min(f[i - 1][j], f[i][j - 1]) + grid[i][j];
}
}
return f[m - 1][n - 1];
}
}
2016年7月26日星期二
[LeetCode] #64 Minimum Path Sum
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