public class Solution {
public List<List<Integer>> combinationSum3(int k, int n) {
List<List<Integer>> result = new ArrayList<>();
if (k < 1 || n < 1 || n > 45) {
return result;
}
helper(result, new ArrayList<Integer>(), 0, k, n, 1); // Attn: starts from 1, not 0
return result;
}
private void helper(List<List<Integer>> result, List<Integer> path, int sum, int k, int n, int start) {
if (path.size() == k && sum == n) {
result.add(new ArrayList<Integer>(path));
return;
}
if (path.size() == k) {
return;
}
for (int i = start; i <= 9; i++) {
if (sum + i > n) {
break;
}
path.add(i);
helper(result, path, sum + i, k, n, i + 1);
path.remove(path.size() - 1);
}
}
}
2016年7月21日星期四
[LeetCode] #216 Combination Sum III
Time complexity: O(2^n)
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